Xavier faces N.C. State Tuesday night in NCAA First Four game

DAYTON, OH (FOX19) - The Xavier Musketeers play in one of the First Four NCAA tournament games Tuesday night.

Xavier is seeded 12th and faces No. 12 seed N.C. State at 9:10 p.m. Tuesday in Dayton, Ohio. The winner faces Midwest region No. 5 seed St. Louis at 7:20 p.m. Thursday in Orlando, Fla.

FOX19's Sara Celi is live from Dayton on Tuesday's FOX19 Morning News.

Xavier (21-12) is making its 24th NCAA tournament appearance. It last appeared in the Big Dance in 2012 when it lost to Baylor in the Sweet 16. Xavier's best finishes in the tournament are two Elite Eight appearances (2004 and 2008).

The Musketeers finished third in the Big East this season.

N.C. State (21-13) is making its 23th appearance in the NCAA tournament. The Wolfpack lost in the second round last year. The Wolfpack won the national championship in 1974 and 1983.

The Wolfpack finished tied for seventh in the ACC this season.

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