Hill wins AFC Player of the Week - Cincinnati News, FOX19-WXIX TV

Hill wins AFC Player of the Week

(PHOTO: FOX19 file) (PHOTO: FOX19 file)
CINCINNATI, OH (FOX19) -

Bengals' rookie running back Jeremy Hill was name the AFC Offensive Player of the Week on Wednesday.

In a 30-0 win over the Cleveland Browns, Hill ran for a team-high 148 yards with two touchdowns.

Hill rushed 25 times for 5.9 yards a carry.

The rookie from LSU is the first Bengal to win the award since last season when Andy Dalton was named Player of the Week against the Indianapolis Colts in Week 14.

The Bengals and Hill will try to clinch a playoff spot with a win against the Denver Broncos on Monday Night at 8:30 p.m.

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